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Continuity at a point (video) | Khan Academy
At which numbers does the function f appear to be NOT continuous? Explain why. What occurs at other numbers in the domain?
We see that the domain of the function is a closed interval at $[0,4]$.
There are break at $x=1$, $x=2$, and $x=4$
The break at $x=1$ is a “jump discontinuity”.
The break at $x=2$ and $x=4$ is a “removable discontinuity”.
We say a function is continuous at a number c if:
$$ \lim_{x\rightarrow c} f(x)=f(c) $$
We say a function is continuous from the right if:
$$ \lim_{x\rightarrow c^+} f(x)=f(c) $$
We say a function is continuous from the left if:
$$ \lim_{x\rightarrow c^-} f(x)=f(c) $$
We say a function is continuous on [a,b] if it is continuous for all $c \epsilon (a,b)$ and continuous from the right at a and continuous from the left at b
“you can draw a line without picking up your pencil”
<aside> 💡 Continuity Test: A function f(x) is continuous at a point $x = c$ if and only if it meets the following three conditions: