Question 2: Use the following function and its graph to answer (a) through (d) below.

$f(x)=\begin{cases}6-x & x<4\\ -\frac{3x}{4}+1 & x >4\ \end{cases}$

• Solution:

Question 4: Graph the function then answer these question.

$$ f(x)=\begin{cases}\sqrt{16-x^2}& 0 \leq x<4\\ 4& 4\le x<8\\8 & x=8\end{cases} $$

a) What are the domain and range of f?

b) At what points c, if any, does $\lim_{x \rightarrow c} f(x)$ exist?

c) At what points does only the left-hand limit exist?

d) At what points does only the right-hand limit exist?

• Solution: